Контрольная работа по "Методу математического моделирования"
Автор: zhasko • Июнь 28, 2023 • Контрольная работа • 4,110 Слов (17 Страниц) • 135 Просмотры
- f min =x1+2x2
[pic 1]
[pic 2]
[pic 3]
[pic 4]
[pic 5]
4 С
3
В
2
1[pic 6]
1 Д2 3 4 5
-5 -4 -3 -2 -1
-1 . . .
-2
-3
-4[pic 7]
[pic 8][pic 9]
Жауабы: [pic 10][pic 11]
Симплекс әдісі.
3.2. fmin =-2x1+x2-3x3+0x4+0x5+0x6 fmax =2x1-x2+3x3+0x4+0x5+0x6
[pic 12] [pic 13]
2 -1 3 0 0 0
N | Б | Сб. | в | X1 | X2 | X3 | X4 | X5 | X6 |
1 | x4 | 0 | 8 | 3 | 0 | -1 | 1 | 0 | 0 |
2 | x5 | 0 | 1 | -1 | 1 | 4 | 0 | 1 | 0 |
3 | x6 | 0 | 6 | 2 | 1 | -3 | 0 | 0 | 1 |
m+1 | - | - | 0 | -2 | 1 | -3 ↑ | 0 | 0 | 0 |
1 | x4 | 0 | 33/4 | 11/4 | 1/4 | 0 | 1 | 1/4 | 0 |
2 | x3 | 3 | 1/4 | -1/4 | 1/4 | 1 | 0 | 1/4 | 0 |
3 | x6 | 0 | 27/4 | 5/4 | 7/4 | 0 | 0 | 3/4 | 1 |
m+1 | - | - | 3/4 | -11/4↑ | 7/4 | 0 | 0 | 3/4 | 0 |
1 | x1 | 2 | 3 | 1 | 1/11 | 0 | 4/11 | 1/11 | 0 |
2 | x3 | 3 | 1 | 0 | 3/11 | 1 | 1/11 | 3/11 | 0 |
3 | x6 | 0 | 3 | 0 | 18/11 | 0 | -5/11 | 7/11 | 1 |
m+1 | - | - | 9 | 0 | 2 | 0 | 1 | 1 | 0 |
Кестеге түсініктеме: 1) 1/4 -1/4 1/4 1 0 1/4 0
...